### Properties of Fluid Problem 1 – Properties of Fluid – Fluid Mechanics

hello friends here in this video we will see the problem on properties of fluid let us take the question number one we have here calculate specific weight density and specific gravity of one liter of a liquid which weighs seven Newton now this is the question we have I will write the data for this so given data here we have to calculate specific weight that is the first question specific weight is nothing but weight density denoted by a small W next density is mass density denoted by Rho then the third one is specific gravity denoted by a small s of one liter this one liter is the volume of the liquid so here we have V is equal to one liter and one liter is nothing it is equal to 10 raise to minus 3 meter cube how this relation came because since one meter cube can contain thousands liter of water so therefore one liter is equal to it will be one divided by thousand so 10 raised to minus 3 meter cube so here is the conversion part now this is the question we have in front of us where volume is given and they have even given the volume of a liquid which weighs 7 Newton so capital W weight of the liquid is 7 Newton now let us try to get the solution for this problem since the first question is specific weight or weight density I will start from here since specific weight or weight density is given by it has given by W is equal to weight upon volume this is the relation weight density is the ratio of weight upon volume now I will put the values here so therefore specific weight will be equal to weight of the liquid is given as seven volume is 10 raise to minus 3 so therefore a specific weight comes out to be 7000 unit is Newton per meter cube this is the first answer next now the second part we have to calculate mass density so now I’ll say that since mass density we know the relation mass density it is given by mass density is Rho and that is equal to the specific weight or weight density divided by G so here is the relation between mass density and weight density this relation I am utilizing that mass density is weight density divided by G weight density we have got it as 7,000 divided by 9.81 so finally density answer that comes out to be seven hundred and thirteen point five Oh point five kg per meter cube because it is mass per unit volume so this is my second answer and now the last part in this question is specific gravity so I will say that since specific gravity of liquid s is equal to weight density of liquid upon weight density of standard liquid that is water so it is divided by weight density of water so therefore specific gravity is equal to the weight density of liquid we have got an answer one that is seven thousand divided by weight density of water that is thousand so here we have via right okay via writing weight density weight density of water is it is given by nine eight one zero this is the mass density of water and the weight density is it is nine eight one zero so finally how I got this because thousand is the mass density and in that if I multiply with G that is nine point eight one that gives me an answer of nine eight one zero so therefore if I divide numerator by denominator my answer of s it comes out to be zero point seven one three five so this much is the specific gravity of the given liquid and since this value is less than one it means the specific gravity the liquid we have here it is lighter than water because the specific gravity is less than one if the specific gravity is equal to 1 then it is water if the specific gravity is more than one then the given liquid is heavier than water so this was a simple problem related to properties of fluid

## 38 thoughts on “Properties of Fluid Problem 1 – Properties of Fluid – Fluid Mechanics”

1. prakash pal says:

please sir provide full lecture of FM because we have complite notes so please

2. gurpreet singh says:

this playlist not available ??

3. Paresh Patil says:

Thank you sir , preparing for exam from your lectures.

4. ramakrishna Peram says:

thank you soooomuch sir

5. Himanshu Gupta says:

crystal clear

6. ajay sahu says:

Hello sir, I cannot find this playlist, it was there 1 week back, please bring it back we have our exams

7. Nilesh Sonawane says:

sir civil ke hydrolics pe videos banao plzz….

8. Ram Kumar says:

in this viedo we understand clearly

9. Mahammadamir Shaikh says:

thank you sir . beautiful explenation.

10. saurabh kumar singh says:

tooo gud sir dil kush ho gya…

11. Rahul Kumar says:

Sir can you refer a book of fluid mechanics for us…

12. Shoiab says:

Nice initiative to help the students'
Beautifully expanded lectures
Need all other lectures of this perticuar book

13. suraj patel says:

sir please unit explain with dimension

14. Muhammad Hasnain says:

the problems with thier spcific unit.

15. suresh chowdary says:

We can calculate specific gravity directly by ratio of density of liguid to density of water

16. MD HAMID RAJA says:

Ï am happy to you sir and lm mechanica engineer ka pora topics compleet kar dejeye plz

17. Chinmayakanta Behera says:

sir thank u very very much sir

18. Akash kamble says:

Sir appliyed hydroulics pe bhi video upload karo na

19. sameer joshi says:

Sir mass density Ka formula rho =mass of fluid to its volume hai na to ye konsa use kiya hai

20. Abdul Rahaman miya says:

Plz bring all important notes about mechanical engineering 4sem .

21. Aakash says:

Sir please make the videos on kinematics of machine

22. qureshi bilal udgir says:

Sir Make more videos of Hydraulics

23. qureshi bilal udgir says:

And thanks
You are doing great job sir…👌👌👌👏👏👏👏👍👍👍👍🖒🖒🖒

24. Zsyl Echano says:

sir, good day! i fully understand the video, thank you so much. but i got a concern on the value of density that you used in calculating the specific gravity. Rounding off the obtained density value is just equal to 700 and not 7000. although your final answer is correct, the value of density that you plugged in on the specific gravity formula is not. 🙂 thank you.
-zsyl, philippines

25. sajan morbaita says:

Can anyone reccomend me video lectures on hydraulics open channel flow for btech.

26. me Patel says:

Good

27. shahid Ahmad says:

its not meter cube , say it cubic meter

28. Abhinash Kumar says:

Sir density ka formula wrong q rkha hai

29. Harun Or Rashid9899 says:

please sir solved it a math….A hydraulic lift used for lifting automobiles has 20cm diameter ram which can slides in a 20.016cm diameter cylinder .the clearence between the cylinder and ram is filled with an oil pf kinematics viscosity of 3.5cm/s^2 and specific gravity ,SG=0.85 if the ram travels at a uniform velocity of 15 cm/s estimate the frictional resistance experienced by the ram per unit meter of length.

30. selva jai says:

super sir

31. Md. Miran Jawed says:

Great

32. Kolagani ramteja says:

Sir I need problems on topic of fluid dynamics … U can upload this problem… All of them we need … In gate point of questions …. Nd problems ..

33. Devi Prasad says:

Why g=9.81

34. Thanos Jimbruttan says:

Sir..plz give full videos on fm….i don't have money to buy premium member…plz help me sir…

35. STUDY WORLD 3D says:

Nice
#studyworld3d

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37. mohammad mohsin says:
38. anirudh ramesh says: